By concatenating each product, we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3).
The same can be achieved by starting at 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
The aim is to find the largest 1 to k pandigital k-digit number that can be formed as the concatenated product of an integer with (1,2,...,n) where n > 1. Begin by entering the number of digits.